What is the maximum weight a non-fixed 10" x 4 3/4" beam can carry if it spans 10' and has a weight of 25.4lbs per foot?

Prepare for the NEIEP Escalator Components and Installation Procedures Test with comprehensive quizzes, flashcards, and detailed explanations. Elevate your understanding and succeed with confidence!

To determine the maximum weight a non-fixed beam of specified dimensions and weight can carry, we must consider several key factors. For a 10" x 4 3/4" beam spanning 10 feet (or 120 inches) and having a weight of 25.4 lbs per foot, the total weight of the beam itself can be calculated first.

The total weight of the beam is the weight per foot multiplied by the length in feet. In this case, it's 25.4 lbs/foot × 10 feet, which equals 254 lbs. This weight affects how much additional load the beam can support.

Next, we look at the beam's moment capacity and its design considerations—specifically, how it behaves under load. In engineering design, non-fixed beams have certain load-carrying capacities determined by their material properties, cross-sectional dimensions, and the effects of bending, shear, and deflection.

Given common engineering practices and supportive guidelines, a non-fixed 10" x 4 3/4" beam under these conditions (considering factors such as allowable bending stress and deflection limits) would typically have a calculated safe load capacity. The value of 8,000 lbs indicates that, factoring in the

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy